Multiply the number of calcium atoms by 3 and the number of phosphorus atoms by 2. Phosphorus goes from 0 to -3, gaining 3 electrons (oxidation).Calcium goes from 0 to +2, losing 2 electrons (reduction).Identify the changes in oxidation numbers:.In Ca 3P 2, calcium has an oxidation number of +2, and phosphorus has an oxidation number of -3.Phosphorus (P) also has an oxidation number of 0 in its elemental form.
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